Let G be a simply connected absolutely simple algebraic group defined overthe field of real numbers R. Let H be a simply connected semisimple R-subgroupof G. We consider the homogeneous space X=G/H. We ask: How many connectedcomponents has X(R)? We give a method of answering this question. Our method is based on oursolutions of generalized Reeder puzzles.
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机译:令G为在实数R的场上定义的简单连接的绝对简单代数组。令H为G的简单连接的半简单R-子组。我们考虑齐次空间X = G / H。我们问:X(R)有多少个连接组件?我们给出了回答这个问题的方法。我们的方法基于广义Reeder难题的解决方案。
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